A force F=20+10y acts on a particle in y...

A force `F=20+10y` acts on a particle in y-direction where F is in Newton and y in meter. Wrok done by this force to move the particle from `y=0` to `y=1 m` is:

20 J

30 J

5 J

25 J

Text Solution

Verified by Experts

The correct Answer is:

Work done by variable force `= intF .dy`
Work done `=int_(y=0)^(y=1) F.dy =int_0^1 (20+10y) dy`
`=[20y+10/2y^2]_0^1`
`=20 +10/2 = 25 J`

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