Work done is splitting a drop of water of 1 mm radius into 64 droplets is (surface tension of water =72xx10^(-3)j m^(2))`

Options

A. `9.58 xx10^(-5) J`
B. `8.95 xx10^(-5) J`
C. `5.89 xx10^(-5) J`
D. `5.98 xx10^(-6) J`

Answer

B

Explanation

`4/3 piR^3 =n4/3pi(r)^3implies r=R/(n^(1//3))`
`W=4piT[n(R/(n^(1//3)))^2 -R^2]=4piR^2T[n^(1//3)-1]`
`=4pixx(1xx10^(-3))^2 xx72 xx10^(-3) (10^(6//3) -1) =8.95 xx10^(-5) J`