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The excess pressure inside one soap bubb...

The excess pressure inside one soap bubble is three times that inside a second bubble. The ratio of the volume of first bubble to that of the second

A

`1:9`

B

`1:3`

C

`3:1`

D

`1:27`

Text Solution

Verified by Experts

The correct Answer is:
A
`(DeltaP_1)/(DeltaP_2)=R_2/R_1 implies3/1 =R_2/R_1implies R_1/R_2=1/3`
`:. S_1/S_2=(4piR_1^2)/(4piR_2^2)=(1/3)^2=1:9`
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