The pressure inside a small air bubble of radius `0.1`mm situated just below the surface of water will be equal to [Take surface tension of water `70xx10^-3Nm^-1` and atmospheric pressure`=1.013xx10^5Nm^-2`]

Options

A. `2.054 xx10^3` Pa
B. `1.027 xx10^3` Pa
C. `1.027 xx10^5` Pa
D. `2.054 xx10^5` Pa

Answer

C

Explanation

Excess pressure `=(2sigma)/r`
`implies P_("in")-P_("out") =(2sigma)/r`
`implies P_("in")= (2xx7 xx10^(-3))/(0.1xx10^(-3))+1.013xx10^(5)`
`=1.027xx10^5 Pa`