The total kinetic energy of a body of mass 10 kg and radius 0.5 m moving with a velocity of 2 m/s without slipping is 32.8 joule. The radius of gyration of the body is

Options

A. 0.25m
B. 0.2m
C. 0.5m
D. 0.4m

Answer

D

Explanation

Total `K.E. = (1)/(2) mv^(2) (1+ (K^(2))/(R^(2)))= 32.8`
`rArr (1)/(2) xx 10 xx (2)^(2) [1+ (K^(2))/((0.5)^(2))] = 32.8`
`rArr K= 0.4m`