A rigid body of mass m rotates with angular velocity `omega` about an axis at a distance a from the centre of mass G. The radius of gyration about a parallel axis through G is k. The kinetic energy of rotation of the body is

Options

A. `(1)/(2) mK^(2) omega^(2)`
B. `(1)/(2) ma^(2) omega^(2)`
C. `(1)/(2) m(a^(2) + K^(2)) omega^(2)`
D. `(1)/(2) m(a + K^(2)) omega^(2)`

Answer

C

Explanation

`I= mK^(2) + ma^(2)`
`K_(R)= (1)/(2) m (K^(2) + a^(2)) omega^(2)`