A meter stick is held vertically with one end on the floor and is allowed to fall. The speed of the other end when it hits the floor assuming that the end at the floor does not slip is `(g=9.8 m//s^(2))`

Options

A. 3.2m/s
B. 5.4m/s
C. 7.6 m/s
D. 9.2m/s

Answer

B

Explanation

Law of conservation energy – `mgh= (1)/(2) I omega^(2)`
`rArr mg ((l)/(2)) = (1)/(2) I omega^(2)= (1)/(2) (ml^(2))/(3) ((v_(B))/(l.l))^(2)`
`rArr v_(B)= sqrt(3gl) = sqrt(3 xx 9.8 xx 1)= 5.4 m//s`