The moment of inertia of a rod about an axis through its centre and perpendicular to it, is `(1)/(12)ML^(2)` (where, M is the mass and L is length of the rod). The rod is bent in the middle, so that two halves make an angle of `60^(@)`. The moment of inertia of the bent rod about the same axis would be

Options

A. `(1)/(48) ML^(2)`
B. `(1)/(12) ML^(2)`
C. `(1)/(24) ML^(2)`
D. `(ML^(2))/(8 sqrt3)`

Answer

B

Explanation

`I= ((M)/(2) ((L)/(2))^(2))/(3) + ((M)/(2) ((L)/(2))^(2))/(3)`

`= (ML^(2))/(12)`