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A constant torque of 31.4 N-m is exterte...

A constant torque of `31.4 N-m` is exterted on a pivoted wheel. If the angular acceleration of the wheel is `4 pi rad//s^2`, then the moment of inertia will be.

A

`2.5 kg - m^(2)`

B

`3.5 kg - m^(2)`

C

`4.5 kg- m^(2)`

D

`5.5 kg- m^(2)`

Text Solution

Verified by Experts

The correct Answer is:
A
`tau= 31.4 N-m, alpha= 4pi "rad/sec"^(2)`
`tau= I alpha rArr I= (31.4)/(4pi) = 2.5 kg m^(2)`
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