Two rotating bodies `A` and `B` of masses `m` and `2m` with moments of inertia `I_(A)` and `I_(B) (I_(B) gt I_(A))` have equal kinetic energy of rotation. If `L_(A)` and `L_(B)` be their angular momenta respectively, then

Options

A. `L_(A) gt L_(B)`
B. `L_(A)= (L_(B))/(2)`
C. `L_(A)= 2L_(B)`
D. `L_(B) gt L_(A)`

Answer

A

Explanation

`KE_(A)= KE_(B)`
`(1)/(2) I_(A) omega_(A)^(2) = (1)/(2) I_(B) omega_(B)^(2) rArr` Since `I_(B) lt I_(A)`, So `omega_(B) gt omega_(A)`
`(1)/(2) L_(A) omega_(A) = (1)/(2) L_(B) omega_(B) rArr L_(B) lt L_(A)`