A uniform rod of length 200cm and mass 5...

A uniform rod of length 200cm and mass 500g is balanced on a wedge placed at 40 cm mark. A mass of 2Kg is suspended from the rod at 20cm and another unknown mass m is suspended from the rod at 160cm mark as shown in figure. Find value of m such that the rod is in equilibrium.

(1/3) kg

(1/6) kg

(1/12) kg

(1/2) kg

Text Solution

Verified by Experts

The correct Answer is:

By balancing torque
`2g xx 20 = 0.5g xx 60 + mg xx 120`
`m = (0.5)/(6) kg= (1)/(12) kg`

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