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A thermodynamic system undergoes cyclic ...

A thermodynamic system undergoes cyclic process `ABCDA` as shown in figure. The work done by the system is

A

`P_0V 0`

B

`2P_0V_0`

C

`(P_0 V_0)/(2)`

D

Zero

Text Solution

Verified by Experts

The correct Answer is:
D
Work done (`W_(BCOB)`)= -area of triangle BCO = `-1/2 P_0V_0`
Work done (`W_(AODA)`) = + area of triangle AOD = `1/2 P_0V_0`
`W_("net")=0`.
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