A constant amount of an ideal gas undergoes the cyclic process ABCA in the PV diagram shown below The path BC is an isothermal. The work done by the gas during one complete cycle, beginning and ending at A, is nearly-

Options

A. 600 kJ
B. 300 kJ
C. -300 kJ
D. -600 kJ

Answer

C

Explanation

`W_(CrarrA)=0`
Process BC, T = constant
`P_C V_C=P_B V_B`
`500 xx 2=200 xx V_B`
`V_B=5M^3 implies W_(A+B)=200[V_B-V_A]=200[5-2]=600`
`W_(BrarrC) gt W_(Ararr B)" ":.` Net work done is -ve.