One mole of an ideal gas at an initial t...

One mole of an ideal gas at an initial temperature true of `TK` does `6R` joule of work adiabatically. If the ratio of specific heats of this gas at constant pressure and at constant volume is `5//3`, the final temperature of the gas will be

A

(T+2.4) K

B

(T-2.4)K

C

(T+4)K

D

(T-4)K

Text Solution

Verified by Experts

The correct Answer is:

D

Work done (W) = `(nR(T_i-T_f))/(gamma-1)`
`implies 6R = (R(T-T_f))/((5/3-1)) implies T_f = (T-4)K`

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