The temperature inside a refrigerator is `t_2` °C and the room temperature is `t_1` °C. The amount of heat delivered to the room for each joule of electrical energy consumed ideally will be

Options

A. `(t_1+t_2)/(t_1+273)`
B. `(t_1)/(t_1-t_2)`
C. `(t_1+273)/(t_1-t_2)`
D. `(t_2+273)/(t_1-t_2)`

Answer

D

Explanation

`(Q_("less"))/(W) = (Q_("less"))/(Q_("more")-Q_("less")) =(T_("less"))/(T_("more")-T_("less"))`
`=(t_2 + 273)/((t_1+273)-(t_2+273))=(t_2+273)/(t_1-t_2)`