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A wheel of radius 0.4m can rotate freely...

A wheel of radius `0.4m` can rotate freely about its axis as shown in the figure. A string is wrapped over its rim and a mass of `4 kg` is hung. An angular acceleration of `8 rad//s^(2)` is produced in it due to the torque. Then, the moment of inertia of the wheel is (`g=10m//s^(2)`)

A

`2"kg-m"^(2)`

B

`1"kg-m"^(2)`

C

`4"kg-m"^(2)`

D

`8"kg-m"^(2)`

Text Solution

Verified by Experts

The correct Answer is:
A
`tau=Fr_(_|_)=4xx10xx0.4=16 N-m`
Now, `tau=IalphaimpliesI=(16)/(8)=2 "kg-m"^(2)`
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