A torque of 30 N-m is acting on a wheel of mass 5 kg and moment of inertia `2 kg-m​^(2)`​. If wheel starts rotating from rest then its angular displacement in 10 seconds will be-

Options

A. `750` rad.
B. `1500` rad.
C. `3000` rad.
D. `6000` rad

Answer

A

Explanation

`alpha=(tau)/(I)=(30)/(2)=15"rad/sec"^(2)`
`theta=omega_(0)t+(1)/(2) alphat^(2)=0+(1)/(2)xx15xx(10)^(2)=750` rad .