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A rod of weight w is supported by two pa...

A rod of weight `w` is supported by two parallel knife edges `A` and `B` and is in equilibrium in a horizontal position. The knives are at a distance `d` from each other. The centre of mass of the rod is at a distance `x` from `A`.

A

`(Wd)/(x)`

B

`(W(d-x))/(x)`

C

`(W(d-x))/(d)`

D

`(Wx)/(d)`

Text Solution

Verified by Experts

The correct Answer is:
C
`N_(A)+N_(B)=mg=W`
`N_(A)x=N_(B)(d-x)`
implies `N_(A)x=(mg-N_(A))(d-x)`
implies `N_(A)x=W(d-x)-N_(A)(d-x)`
`implies N_(A)d=W(d-x)impliesN-(A)=(W(d-x))/(d)`
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