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A light rod of length l has two masses m...

A light rod of length `l` has two masses `m_1` and `m_2` attached to its two ends. The moment of inertia of the system about an axis perpendicular to the rod and passing through the centre of mass is.

A

`sqrt(m_(1)m_(2)l^(2))`

B

`(m_(1)m_(2))/(m_(1)+m_(2))l^(2)`

C

`(m_(1)+m_(2))/(m_(1)m_(2))l^(2)`

D

`(m_(1)+m_(2))l^(2)`

Text Solution

Verified by Experts

The correct Answer is:
B


`I=m_(1)r_(1)^(2)+m_(2)r_(2)^(2)`,
Here , `r_(1)=(m_(2)l)/((m_(1)+m_(2)))` and `r_(2)=(m_(1)l)/((m_(1)+m_(2)))`
`impliesI=m_(1)((m_(2))/(m_(1)+m_(2))l)^(2)+m_(2)((m_(1))/(m_(1)+m_(2))l)^(2)` `:.I=(m_(1)m_(2)l^(2))/((m_(1)+m_(2)))`.
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