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Two rigid bodies A and B rotate with rot...

Two rigid bodies A and B rotate with rotational kinetic energies `E_(A)` and `E_(B)` respectively. The moments of inertia of A and B about the axis of rotation are `I_(A)` and `I_(B)` respectively. If `I_(A) = I_(B)//4` and E_(A)= 100 E_(B), the ratio of angular momentum (L_(A)) of A to the angular momentum (L_(B)) of B is

A

25

B

`5//4`

C

`5`

D

`1//4`

Text Solution

Verified by Experts

The correct Answer is:
C
`(K_(A))/(K_(B))=(L_(A)^(2))/(2I_(A))xx(2I_(B))/(L_(B)^(2))`
`implies100=(L_(A)^(2))/(L_(B)^(2))xx4implies(L_(A))/(L_(B))=5`
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