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A body of mass m slides down an incline ...

A body of mass `m` slides down an incline and reaches the bottom with a velocity `v`. If the same mass were in the form of a ring which rolls down this incline, the velocity of the ring at the bottom would have been

A

v

B

`sqrt(2)v`

C

`(1)/(sqrt(2))v`

D

`sqrt((2)/(5))v`

Text Solution

Verified by Experts

The correct Answer is:
C
`v=sqrt(2gh)`
`v.=sqrt((2gh)/(1+(K^(2))/(R^(2))))=sqrt(gh)=(v)/(sqrt(2))` `[ :. "for ring" (K^(2))/(R^(2))=1]`
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