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A uniform rod of length 200cm and mass 5...

A uniform rod of length 200cm and mass 500g is balanced on a wedge placed at 40 cm mark. A mass of 2Kg is suspended from the rod at 20cm and another unknown mass m is suspended from the rod at 160cm mark as shown in figure. Find value of m such that the rod is in equilibrium.

A

`(1//3)kg`

B

`(1//6)kg`

C

`(1//12)kg`

D

`(1//2)kg`

Text Solution

Verified by Experts

The correct Answer is:
C

By balancing torque
`2gxx20=0.5gxx60+mgxx120`
`m=(0.5)/(6)kg=(1)/(12)kg`
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