If a charged spherical conductor of radius `10 cm` has potential `V` at a point distant `5 cm` from its centre, then the potential at a point distant `15 cm` from the centre will be

Options

A. `1/3 V`
B. `2/3 V`
C. `3/2 V`
D. 3V

Answer

B

Explanation

`V_("in")= V_("surface") = ` constant
`V= V_("surface") = (Kq)/((0.1)), V_("out") =(Kq)/(0.15)`
`V_("out")/V=10/15=2/3 implies V_("out") = 2/3V`