Two electric charges `12 mu C` and `-6 mu C` are placed `20 cm` apart in air. There will be a point `P` on the line joining these charges and outside the region between them, at which the electric potential is zero. The distance of `P` from `6 mu C` chrage is

Options

A. 0.10 m
B. 0.15 m
C. 0.20 m
D. 0.25 m

Answer

C

Explanation

`V_P=0`

`implies (K xx12 xx10^(-6))/(x+20)=(Kxx6 xx10^(-6))/x`
`implies 2x = x+ 20`
`implies x = 20 cm = 0.20 m`