The electric potential at a point in free space due to a charge `Q` coulomb is `Q xx 10^(11)` volts. The electric field at that point is

Options

A. `4piepsilon_0Q xx 10^(20) V//m`
B. `12piepsilon_0Q xx 10^(22) V//m`
C. `4piepsilon_0Q xx 10^(22) V//m`
D. `12piepsilon_0Q xx 10^(20) V//m`

Answer

C

Explanation

`V=(KQ)/rimpliesQxx10^(11) =(KQ)/rimpliesK/r =10^(11)`
`E=(KQ)/r^2=((KQ)/r)^2xx1/(KQ)=(Qxx10^(11))^(2) xx1/(KQ)`
`implies E = 4piepsilon_0 xxQ xx 10^(22) V//m`