Two charged spheres having radii a and `b` are joined with a wire then the ratio of electric field `E_(a)/E_(b)` on their respective surfaces is ?

Options

A. `a//b`
B. `b//a`
C. `a^2//b^2`
D. `b^2//a^2`

Answer

B

Explanation

`V_1=V_2implies (KQ_1)/a=(KQ_2)/bimpliesQ_1/Q_2=a/b`
`E_1=(KQ_1)/(a^2)and E_2(KQ_2)/(b^2)`
`E_1/E_2=(KQ_1)/a^2xxb^2/(KQ_2)=a/bxxb^2/a^2=b/a`