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Electric potential is given by V = 6x ...

Electric potential is given by
`V = 6x - 8xy^(2) - 8y + 6yz - 4z^(2)`
Then electric force acting on `2C` point charge placed on origin will be

A

2N

B

6N

C

8N

D

20N

Text Solution

Verified by Experts

The correct Answer is:
D
`V=6x - 8xy^2 -8y +6yz -4z^2`
`vecE=-((delV)/(delx)hati+(delV)/(dely)hatj+(delV)/(delz)hatk)`
`=-(6-8y^2)hati-(-16xy-8+6z)hatj-(6y-8z)hatk`
At (0, 0, 0)
`vecE =-6hati +8hatjimplies |vecE| =10 N//C`
Force `(F) = qE = 2xx10=20 N`
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