An electron of mass m and charge q is accelerated from rest in a uniform electric field of strength E. The velocity acquired by it as it travels a distance l is

Options

A. `[(2Eql)/(m)]^(-1//2)`
B. `[(2Eq)/(ml)]^(1//2)`
C. `[(2Em)/(ql)]^(1//2)`
D. `[(Eq)/(ml)]^(1//2)`

Answer

A

Explanation

`1/2 mv^2 =qV=qEl`
`v = [(2qEl)/m]^(1//2)`