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An electric falls through a distance of...

An electric falls through a distance of 1.5 cm in a uniform electric field of magnitude `2 xx 10^(4) N//C`. Now the direction of the field is reversed keeping the magnitude unchanged and a proton falls through the same distance. Compute the time of fall in each case, neglecting gravity .

A

Same in both cases

B

More in the case of an electron

C

More in the case of proton

D

Independent of charge

Text Solution

Verified by Experts

The correct Answer is:
C
`d=1/2"at"^2 =1/2 ((qE)/(m))t^2 implies t =sqrt((2dm)/(qE))`
`t prop sqrtm`
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