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An electric dipole of length 1 cm is pla...

An electric dipole of length 1 cm is placed with the axis making an angle of `30^(@)` to an electric field of strenght `10^(4) NC^(-1)` . If it experience a taroue of `10 sqrt(2)Nm` , the potential energy of the dipole is :

A

0.245 J

B

2.45 J

C

0.0245 J

D

24.5 J

Text Solution

Verified by Experts

The correct Answer is:
D
`2a =1 cm = 1 xx10^(-2) m , theta = 30^@ ` with E
`E = 10^4 N//C " "tau = 10sqrt2 Nm`
`vectau = vecp xxvecE = pE sin 30^@`
`implies 10sqrt2=p xx10^4 xx1/2 , p = 20 sqrt2 xx10^(-4) cm`
`U=-pE cos 30^@ =-20 sqrt2 xx10^(-4) xxsqrt3/2`
`=-10 sqrt6J = 24.5 J`
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