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The electric flux for Gaussian surface A...

The electric flux for Gaussian surface `A` that enclose the charge particles in free space is (given `q_(1)= -14nC,q_(2)= 78.85nC,q_(3)= -56nC)`

A

`10^3 Nm^2 C^(-1)`

B

`10^3 Nm^(-1) m^(-2)`

C

`6.32 xx10^3 Nm^2 C^(-1)`

D

`6.32 xx10^3 CN^(-1) m^(-2)`

Text Solution

Verified by Experts

The correct Answer is:
A

`phi=q_("in")/(epsilon_0)=((-14 + 78.85-56)xx10^(-9))/(8.85 xx10^(-12))=10^3 Nm^2 //C`
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