five charge `q_(1),q_(2),q_(3),q_(4)`and `q_(5)` are fixed at their positions as shown in figure .`s` is Gaussian surface .The Gauss's law is given by `ointvec(E).vec(ds)=(q)/(epsilon_(0))`

Which of the following statement is correct?

Options

A. E on the LHS of the above equation will have a contribution from `q_1,q_5 and q_1,q_5 and q_3` while q on the RHS will have a contribution from `q_2 and q_4` only
B. E on the LHS of the above equation will have a contribution from all charges while q on the RHS will have a contribution from `q_2 and q_4` only
C. E on the LHS of the above equation will have a contribution from all charges while q on the RHS will have a contribution from `q_1,q_3 and q_5` only
D. Both E on the LHS and q on the RHS will have contributions from q2 and q4 only

Answer

B

Explanation

According to Gauss law, the term q on the right side of the equation `int_(s) E.dS =q/(epsilon_0)` includes the sum of all charges enclosed by the surface.
The charges may be located anywhere inside the surface, if the surface is so chosen that there are some charges inside and some outside, the electric field on the left side of equation is due to all the charges, both inside and outside S .
So, E on LHS of the above equation will have a contribution from all charges while q on the RHS will have a contribution from `q_2 and q_4` only.