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The potential energy of a charged parall...

The potential energy of a charged parallel plate capacitor is `U_(0)`. If a slab of dielectric constant `K` is inserted between the plates, then the new potential energy will be

A

`U_0/k`

B

`U_0k^2`

C

`U_0/k^2`

D

`U_0^2`

Text Solution

Verified by Experts

The correct Answer is:
A
`U_0 = Q^2/(2C)`
When a slab of dielectric constant then k is inserted then
`C. =kC`
`:. U. =Q^2/(2(kC))=U_0/k`
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