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In a parallel plate capacitor with plate...

In a parallel plate capacitor with plate area A and charge Q, the force on one plate because of the charge on the other is equal to

A

`Q^2/(epsilon_0A^2)`

B

`Q^2/(2epsilon_0A^2)`

C

`Q^2/(epsilon_0A)`

D

`Q^2/(2epsilon_0A)`

Text Solution

Verified by Experts

The correct Answer is:
D
`E=sigma/(2epsilon_0)=Q/(2Aepsilon_0),F=QE=Q^2/(2Aepsilon_0)`
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