Eight drops of mercury of equal radii possessing equal charges combine to from a big drop. Then the capacitance of bigger drop compared to each individual small drop is

Options

A. 8 times
B. 4 times
C. 2 times
D. 32 times

Answer

C

Explanation

Volume of 8 small drops = Volume of big drop
`8 xx4/3 pir^3 =4/3 piR^3 impliesR=2r`
As capacity is proportional to r, hence capacitance of bigger drop becomes 2 times.