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0.2 F capacitor is charged to 600 V by a...

`0.2 F` capacitor is charged to `600 V` by a battery. On removing the battery it is connected with another parallel plate condenser of `1 F`. The potential decreases to

A

100 volts

B

120 volts

C

300 volts

D

600 volts

Text Solution

Verified by Experts

The correct Answer is:
A

`V_(0.2) = ((0.2)/(1+0.2))xx600 = 100` Volt .
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