Consider a parallel plate capacitor of `10 muF` (micro-farad) with air filled in the gap between the plates. Now one half of the space between the plates is filled with a dielectric of dielectric constant `4`, as shown in the figure. The capacity of the capacitor charges to

Options

A. `25 muF`
B. `20 muF`
C. `40 muF`
D. `5 muF`

Answer

A

Explanation

`C_(eq) = C_1+C_2=(A/2epsilon_0k)/d+(A/2epsilon_0)/d`
`=(Aepsilon_0)/(2d)(k+1) =10/2xx5 =25muF`