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In the circuit shown here C(1) = 6muF, C...

In the circuit shown here `C_(1) = 6muF, C2 = 3muF` and battery `B = 20V`. The Switch `S_(1)` is first closed. It is then opened and afterwards `S_(2)` is closed. What is the charge finally on `C_(2)`

A

`120 muC`

B

`80 muC`

C

`40 muC`

D

`20 muC`

Text Solution

Verified by Experts

The correct Answer is:
C
When `S_1` is closed
`Q = C_1V = 6 xx200 = 120 muC`
When `S_1 ` is opened and `S_2` is closed
`Q_2=(3/(3+6)) xx120 =40muC`
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