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Two capacitors of capacitances 3 muF and...

Two capacitors of capacitances `3 muF` and `6 muF` are charged to a potential of `12 V` each. They are now connected to each other, with the positive plate of each joined to the negative plate of the other. The potential difference across each will be

A

6 volt

B

4 volt

C

4 volt

D

Zero

Text Solution

Verified by Experts

The correct Answer is:
B

`V= (C_1V_1-C_2V_2)/(C_1+C_2)=(3xx12)/9=`4 Volt.
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