In the given circuit switch K is open. The charge on the capacitor is C is steady-state is `q_1` Now the key is closed and steady-state charge on C is `q_2` The ratio of charges `q_1//q_2` is -

Options

A. `3/2`
B. `2/3`
C. 1
D. `1/2`

Answer

A

Explanation

When key is open –
`q_1=CE` [charge in steady state]
When key is closed –
`V_C = (2R)/(R+2R) E =2/3E`
[potential difference across capacitor]
`q_2 =2/3 CE` [charge in steady state]
`impliesq_1/q_2 =3/2`