A capacitor of capacitance `C_(1)=1 muF` can withstand maximum voltage `V_(1)=6 kV` and another capacitor of capacitance `C_(2)=3 muF` can withstand maximum voltage `V_(2) =4 kV`. When the two capacitors are connected in series, the combined system can withstand a maximum voltage of

Options

A. 4kV
B. 6kV
C. 8kV
D. 10kV

Answer

C

Explanation

`(Q_1)_("max") =1 xx6 = 6mC`
`(Q_2)_("max") =3 xx4 = 12mC`
In series connection charge should be same
`(Q)_("max")=6mC`
`:. V_2 = (6mC)/(3muF) = 2kV`
`:. ` Total potential `V= 6+2=8kV`