An electron is moving in a circular path...

An electron is moving in a circular path under the influence of a transverse magnetic field of `3.57xx10^(-2)` T.If the value of e/m is `1.76xx10^11` c/kg, the frequency of revolution of the electron is

62.8 MHz

6.28 MHz

1 GHz

100 MHz

Text Solution

Verified by Experts

The correct Answer is:

`f=(eB)/(2pim)`
`f=(1.76 xx10^(11) xx3.57 xx10^(-2))/(2xx3.14) `
`f=10^9 `Hz or 1 GHz

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