`A 40 muF` capacitor in a defibrillator is charged to `3000 V`. The energy stored in the capacitor is sent through the patient during a pulse of duration `2 ms`. The power delivered to the patient is

Options

A. 45 kW
B. 90 kW
C. 180 kW
D. 360 kW

Answer

B

Explanation

`U=1/2 CV^2 =1/2 xx40 xx10^(-6) xx 9 xx10^6`
`= 180 J`
Power `=U/t = 180/(2xx10^(-3))=90 xx10^3 = 90 kW`