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A wheel of radius 1 m rolls forward half...

A wheel of radius `1 m` rolls forward half a revolution on a horizontal ground. The magnitude of the displacement of the point of the wheel initially on contact with the ground is.

A

`2pi`

B

`sqrt2 pi`

C

`sqrt(pi^2 + 4)`

D

`pi`

Text Solution

Verified by Experts

The correct Answer is:
C

`A A. = sqrt( (pi R)^2 + (2R)^2)`
`= sqrt(pi^2 + 4)`
Here R = 1m.
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