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The position vector of a particle is det...

The position vector of a particle is determined by the expression `vec r = 3t^2 hat i+ 4t^2 hat j + 7 hat k`. The displacement traversed in first `10` seconds is :

A

500m

B

300m

C

150m

D

100m

Text Solution

Verified by Experts

The correct Answer is:
A
`vecr = (3t^2 hati + 4t^2 hatj + 7 hatk`
`at t = 0, vecr_1= 7 hatk`
at `t = 10 sec, vecr_2 = 300hati + 400hatj + 7hatk`
`vec(Delta r) = vecr_2 - vecr_1 = 300 hati + 400 hatj`
`| vecDeltar = |vecr_2 - vecr_1| sqrt((300)^2 + (400)^2) = 500m`
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