If a car at rest, accelerates uniformly to a speed of `144 km//h` in `20s`, it covers a distance of

Options

A. 20 m
B. 400 m
C. 1440 m
D. 2880 m

Answer

B

Explanation

`a = (144 xx 5/18)/(20) = (v-u)/(t)`
`rArr a = 40/20 = 2m//s^2`
Distance covers-
`S = ut + 1/2 at^2 = 1/2 xx 2 xx (20)^2 = 400m`