The average velocity of a body moving with uniform acceleration after travelling a distance of `3.06 m` is `0.34 m s^(-1)`. If the change in velocity of the body is `0.18 ms^(-1)` during this time, its uniform acceleration is .

Options

A. `0.01 ms^(-2)`
B. `0.02 ms^(-2)`
C. `0.03 ms^(-2)`
D. `0.04 ms^(-2)`

Answer

B

Explanation

Time` = (3.06)/(0.34) = 9sec`
Acceleration ` = (0.18)/(9) = 0.02 m//s^2`