A body moves with initial velocity `10 ms^(-1)` , If it covers a distance of 20m in 2s then acceleration of the body is

Options

A. zero
B. `10ms^(-2)`
C. `5ms^(-2)`
D. `2ms^(-2)`

Explanation

To find the acceleration of the body, we can use the second equation of motion, which relates displacement, initial velocity, time, and acceleration. The equation is given by:

\[ s = ut + \frac{1}{2} a t^2 \]

Where:
- \( s \) = displacement (20 m)
- \( u \) = initial velocity (10 m/s)
- \( t \) = time (2 s)
- \( a \) = acceleration (unknown)

### Step-by-Step Solution:

1. **Identify the known values:**
- Initial velocity \( u = 10 \, \text{m/s} \)
- Displacement \( s = 20 \, \text{m} \)
- Time \( t = 2 \, \text{s} \)

2. **Substitute the known values into the equation:**
\[ 20 = 10 \times 2 + \frac{1}{2} a \times (2^2) \]

3. **Calculate the terms:**
- Calculate \( 10 \times 2 = 20 \)
- Calculate \( 2^2 = 4 \)
- Substitute these values into the equation:
\[ 20 = 20 + \frac{1}{2} a \times 4 \]

4. **Simplify the equation:**
\[ 20 = 20 + 2a \]

5. **Rearrange to solve for \( a \):**
\[ 20 - 20 = 2a \]
\[ 0 = 2a \]

6. **Divide both sides by 2:**
\[ a = 0 \, \text{m/s}^2 \]

### Conclusion:
The acceleration of the body is \( 0 \, \text{m/s}^2 \). This indicates that the body is moving with a constant velocity.