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A body starting from rest moves with con...

A body starting from rest moves with constant acceleration. The ratio of distance covered by the body during the 5th sec to that covered in 5 sec is

A

`9//25`

B

`3//5`

C

`25//9`

D

`1//25`

Text Solution

Verified by Experts

The correct Answer is:
A
Distance covered in 5th second
`S_(5th) = u + a/2 (2xx5-1) = (9a)/(2)`
Distance covered in 5 sec –
`S_5 ut + 1/2 at^2 = (25a)/(2)`
`therefore (S_(5th))/(S_5) = 9/25`
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