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A particle moves along x-axis as x=4(t-2...

A particle moves along x-axis as `x=4(t-2)+a(t-2)^2`
Which of the following is true?

A

The initial velocity of particle is 4

B

The acceleration of particle is 2a

C

The particle is at origin at t = 0

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
B
`x = 4(t - 2) + a (t - 2)^2`
`t = 0, x = -8 + 4a`
`v = (dx)/(dt) = 4 + 2a (t-2)`
`t=0, v = 4-4a`
`a = (dv)/(dt) = 2a`.
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